x^2+64x+8=0

Solution for x^2+64x+8=0 equation:

x^2+64x+8=0

a = 1; b = 64; c = +8;
Δ = b2-4ac
Δ = 642-4·1·8
Δ = 4064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4064}=\sqrt{16*254}=\sqrt{16}*\sqrt{254}=4\sqrt{254}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-4\sqrt{254}}{2*1}=\frac{-64-4\sqrt{254}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+4\sqrt{254}}{2*1}=\frac{-64+4\sqrt{254}}{2}
$